Y=(1/5)x^2-5x+27

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Solution for Y=(1/5)x^2-5x+27 equation: 



=(1/5)Y^2-5Y+27

We move all terms to the left:

-((1/5)Y^2-5Y+27)=0



Domain of the equation: 5)Y^2-5Y+27)!=0

Y!=0/1

Y!=0

Y∈R



We add all the numbers together, and all the variables

-((+1/5)Y^2-5Y+27)=0

We multiply all the terms by the denominator


-((+1=0

We add all the numbers together, and all the variables

=0

Y=0/1

Y=0

Równanie nie ma rozwiązania

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